2k^+9k-3=k-17

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Solution for 2k^+9k-3=k-17 equation: 



2k^+9k-3=k-17

We move all terms to the left:

2k^+9k-3-(k-17)=0

We add all the numbers together, and all the variables

11k-(k-17)-3=0

We get rid of parentheses

11k-k+17-3=0

We add all the numbers together, and all the variables

10k+14=0

We move all terms containing k to the left, all other terms to the right

10k=-14

k=-14/10

k=-1+2/5

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